Added 24-Jan-2025
This is an excellent and simple pattern we can employ just with eye-balling some cells with the same pair of numbers in them. I've placed it near the start of the 'tough' strategies after X-Wing as it is quite common, doesn't require us to think about strong and weak links, and does not take long to evaluate. Very grateful for Andy Potvin from the United States for providing the idea and first examples. [TODO further credits] I will be re-evaluating W-Wings soon and I expect this strategy will be a subset. But it is sufficiently distinct to be worth having on it's own.

If you want to see what CRP replaces, untick it and [<<] (back-step) and [Take Step]

All these examples are from tough puzzles and each has two Chute Remote Pairs in them. In testing I've found some 620 examples in 2000 random diabolicals and I've gained an overall speed increase of about 2%. So it is simplifying the solve paths for more than a quarter of puzzles.

The first example gives the classic pattern. We're looking for two bi-value cells with the same candidates in the same House or Chute (As Andy and many others call it), which is a horizontal or vertical set of the three boxes. There are six houses or chutes in a 9x9 Sudoku.

Both the green cells A8 and C1 here have {4/7}. The next step is to check they can't 'see' each other, ie they are not a Naked Pair but instead a Remote Pair.

Given that pattern there will exist exactly three cells in the unused box in the same chute and I have marked these in yellow {B4, B5, B6).

The rule says, if the yellow cells do NOT contain one of the candidates in the green cells the non-missing candidate can be eliminated from all cells seen by both green cells. I've marked these in pink.

Later on in the puzzle the pattern is found again. We'll try and prove the rule with this second example.

2 and 8 exist in C6 and E5. 2 exists in the third box in J4. Note - it does not matter than this is a clue or solved cell. What is important is the 8 is no where in any of the yellow cells.

If 2 really was the solution to C5 or D6 (the elimination cells) that would force an 8 in one or both of the green cells. However looking down the column that would remove all 8s from box 8 and we can already see there is no 8 in column 4.

The third example contains two Chute Remote Pairs and I've displayed one here.

{7,9} in D6 and F2 form a Remote Pair. Looking horizontally along the house/chute to box 6 we see 9 is present in the yellow cells but 7 is not.

This gives us two eliminations of 9 in D2 and D3. The solver reports:

Chute Remote Pair
7 cannot be set in the yellow cells {E7,E8,E9} and with the Remote Pair in D6 and F2 it means:
9 can be taken off D2
9 can be taken off D3

Now it is possible to extend the rule to eliminate both numbers found in the Remote Pair - but it is much rarer. Normally the puzzle will have made these eliminations with simpler strategies. I found eight double eliminations in 2000 tough puzzles where the single version occured about 245 times.

In the final example {4,7} is not present in any of the yellow cells. It is a coincidence this example has all the yellow cells as clues and solved numbers but it makes checking a little easier

We look around for any 4 or 7 that can be seen by B9 AND C1 and B3 fits the bill.

Chute Remote Pair
Neither 4/7 can be set in the yellow cells {A4,A5,A6} and with the Remote Pair in B9 and C1 it means:
4/7 can be taken off B3

Some further testing running 'Ruud's Top 50,000' through the offline solver I get a 1% speed increase - less than 2% because these have so many more AIC searches to do and AIC dwarfs all other strategies in terms of cost. 16,814 CRPs were used in 14,384 puzzles (28.8%) - a lot but there is a bias since CRP benefits from being so close to the top of the strategy ordering. The strategies that reduce the most are Y-Wings (>3k), XY-Chains (2k), 3D Medusa (1k). Simple Colouring and Rectangle Elimination down by only about ~500.