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#620, November 16 - November 22, 2024:
The Weekly 'Unsolvable' Sudoku Puzzle

by Andrew Stuart

WARNING: This is the Weekly 'Unsolvable' Sudoku, rated above 'Extreme'.
This is currently unsolvable by my solver, except perhaps with trial and error strategies.
Using the solver will not help you. (much).

Archive

Each week a new 'unsolvable' will be published and the previous will be accessible here from this archive section. If you like very tough puzzles, these are for you.
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Supporter Members have access to all these puzzles going back to number 1.

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Wednesday 20-Nov-2024

... by: Serban

# 620 A9=4 B2=6 Basics to 26

1. if F8=5 => F4=7 F6=8 basics to 39
2. X-chain x=6 => [ J4,CE5,A7,D8 ]<>6 ;
X-chain x=9 => GH4<>9 => A7=9 OR G4=4 solve

Monday 18-Nov-2024

... by: Frans Goosens

With trial and error

Combination A3=237 and G9=269

************************************************************
A3=2 G9=2 Wrong, Undo calculation

All reset to initial position

************************************************************
A3=2 G9=6 ( A7=9 ) Solved,

Total solving time is : 25 sec.
Number of logical steps is : 2981

Monday 18-Nov-2024

... by: SM

I don't like Magic Singles/Pairs (like r2c1=9 & r5c7=6). Here's an alternative.

r89c29 can't be solved by 29 (deadly configuration), but that's exactly what would happen if r8c2=2:
bilocation of 2 in r8c89 and r7c9 forces r7c9=2.
bilocation of 9 in r7c2 and r8c2 forces r7c2=9.
so far so easy; for the final stretch (forcing 1 or 2 into r8c9):
8c2=2 → r5c2=1 → r5c7≠1 → r2c7=1 → r2c7≠5 → r89c7=5 → r8c9≠5

Context: [URL of the solver on this site that isn't allowed to be referred to]?bd=S9B01052gaaag1k8i080dbc0f488b8g1d8386079i042e08au1z02928z624309027e5m033m1v050l2l033e093738086048062q014i049w844gbc058qc807c2018k06bd4h8bc04xde9w844407458zck5hci0403

Monday 18-Nov-2024

... by: Serban


# 620 A9=4 B2=6 Basics to 26

1. if B4=5 => F4=7 basics to 28
2. X-chain x=6 => G4<>6 ; X-chain x=9 => G4<>9 ; => G4=H3=D1=E5=B6=4 solve

Saturday 16-Nov-2024

... by: Dieter

#620 - basics: A9=4; B2=6
strategy: try to get hidden pairs or triplets
E3 = (1,2,4,7)
basic checks: E3=1, E3=2 failed
E3=7 & F2=2 solve

Saturday 16-Nov-2024

... by: Serban


# 620 A9=4 B2=6 Basics to 26

1. Number 5 n=3 e=6 N=27 Nc=52 Ns=2 => B4=H6=5 solve

2. Number 6 n =3 e=6 N=23 Nc=20 Ns=6 => E7=J5=6 solve

3. Box 5 DEF456 n=4 e=5 Nc=12 Ns=4 => D5=5 & [E5=4 OR D6=6] solve
Note : F6=8
Page created on 03-May-2011, last modified on 30-May-2024.
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